Prove the converse of the pythagorean theorem using similar triangles. the converse of the pythagorean theorem states that when the sum of the squares of the lengths of the legs of the triangle equals the squared length of the hypotenuse, the triangle is a right triangle. be sure to create and name the appropriate geometric figures.

we have given that δ abc is similar to δ cbd and δ abc is similar to δ acd according to the attached picture.

because of the similarity the corresponding sides are proportional. then a/c = f/a

and b/e = c/b. if we cross multiply, we'll get

a² = cf and b² = ce

if we add these equalities together, we'll get

a² + b² = c (f + e)

from the beginning, we know that c = e+f

then, the final result is:

a² + b² = c²

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )