Given: δabc ≅ δefd
what is the length of segment line fe rounded to the nearest tenth?

Line segment FE is equals to Line segment BA or FE=BA.

B =  (2,4) A = (0,2) 

First we have to subtract the x and y coordinates. 

x = |2 - 0|
x = 2

y = |4-2|
y = 2

Then, we are going to use the Pythagorean Theorem a^2 + b^2 = c^2.

2^2 + 2^2 = 8

Get the square root of 8. The answer will be 2.83. Rounded off to the nearest tenth, the answer will be 2.80

I hope this helped you.


 

Hey bby was a good way i just got