Mathematics, 25.04.2020 05:03 william1690

An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height h at time t seconds after launch is

h(t) = –4.9t2 + 19.6t + 58.8

How many seconds does it take for the object to reach its maximum height?

What is the maximum height of the object?

Answers: 2

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An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation...

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