The population ins a particular country is growing at the rate of 2.5% per year. If 8,911,000 people loved there in 1999, how many will be there in the year 2007?

Population of 10,6993,200

Step-by-step explanation:

8,911,000 x 2.5% =  222,775

There are 8 years from 1999 to 2007.

so multiply 222,775 x 8 =  Then add it to your 8,911,000 and you have your answer.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

he can buy 4lbs. of live bait and 1lbs of natural bait

step-by-step explanation: