All sides of quadrilateral ABCD are tangent to circle P. What is the perimeter of quadrilateral ABCD?

Given:

Let us assume that E,F,G,H be the points at which the circle touches the line segment AB, BC, CD, DA.

The length of EB = 9.6 units.

The length of AH = 3.7 units.

The length of CD = 12 units.

We need to determine the perimeter of ABCD.

Lengths of sides of the quadrilateral ABCD:

Let CG = x, then DG = 12 - x

We know the property the property that "if the lengths of the two tangents drawn from an exterior point to a circle are equal".

Hence, applying the property, we have;

AH = AE = 3.7 units.

EB = BF = 9.6 units.

CG = CF = x units.

DG = DH = (12 - x) units.

Perimeter of quadrilateral ABCD:

The perimeter of ABCD can be determined by adding all the lengths of the sides of the quadrilateral ABCD.

Thus, we have;

Substituting the values, we have;

Thus, the perimeter of the quadrilateral ABCD is 50.6 units.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

step-by-step explanation:

in which figure is point g a centroid