Please help I'm giving 11 pt

These are all in vertex form,

y = a(x - p)² + q

When a is positive this makes a CUP (concave up positive) and has a minimum, not a maximum.  When a is negative then the maximum is just when the squared term is 0, in which case

y = q

is the maximum.

From the figure g(x) has a maximum of 3 at x=2.

A.  Positive coefficient, CUP, no max

B. CUP, no max

C. Negative coefficient, will have a max, at y=3, not greater than 3.

D. Negative coefficient, max at y=4

D

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c