Stacy hits the jackpot one day at the gumball machine. She puts in a quarter and gets 444 gumballs rather than 111. The radius of each gumball is 666 mm.
What is the total volume of all 444 gumballs?
Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi.

3617.28 cubic millimeters.

Step-by-step explanation: I used the formula of a sphere since a gumball is a shape of a sphere and plugged the radius into the formula.

I got that the volume of a single gumball is 288π cubic millimeters.

Since there are 4 gumballs, i multiplied the volume by 4.

The total volume of the four gumballs add up to be 1152π .

Lastly, I multiplied 1152 by pi

and got the answer to be 3617.28 cubic millimeters

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).