What is the equation of a circle with a center at (-4,0)
t passes through the point (-2, 1)?
x2 + (y + 4)2 = square root 5
(x - 1)2 + (y + 2)2 = 5
(x + 4)2 + y2 = 5
(x + 2)2 + (y – 1)2 = square root 5

Step-by-step explanation:

Circle equation:

We need to find h, k , to complete the equation.

(h,k) is center point, in this case is given (-4,0) = (h,k)

h=-4

k=0

Substitute to equation:

Use the initial condition: circle passes through the point (-2,1) = (x,y)

x=-2

y=1

Substitute to equation:

Solve for = 5

Final

astronomers is your final answer! : )

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0