What is a line parallel to y=-x-6 that passes through (-9,-4)?

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

y = -x - 6      The slope is -1, so the parallel line's slope is also -1.

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

y = -x + b      To find b, plug in the point (-9, -4) into the equation, then isolate/get the variable "b" by itself

-4 = -(-9) + b  (two negative signs cancel each other out and become positive)

-4 = 9 + b     Subtract 9 on both sides to get "b" by itself

-4 - 9 = 9 - 9 + b

-13 = b

y = -x - 13

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

the answer will be