"if m= angle aoc=85°, m=angle boc = 2x + 10, and m angle aob = 4x – 15, find the degree measure of angle bocand angle aob. the diagram is not to scale.

a. m= 30°; m= 55°
b. m= 40°; m= 45°
c. m= 45°; m= 40°
d. m= 55°; m= 30°"

Given:

Angle AOC =  85°

Angle BOC = 2x + 10

Angle AOB = 4x - 15

Angle AOB + Angle BOC = Angle AOC

2x + 10 + 4x - 15 = 85

6x - 5 = 85

6x = 85 + 5

6x = 90

6x/6 = 90/6

x = 15

Angle AOB = 2x + 10 = 2(15) + 10 = 30 + 10 = 40

Angle BOC = 4x - 15 = 4(15) - 15 = 60 - 15 = 45

Find the degree measure of Angle BOC and Angle AOB

Answer is: C. m= 45°; m= 40°

Step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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