Triangle XYZ is shown on the coordinate plane below:

Triangle XYZ on the coordinate plane with ordered pairs at X 1, negative 3, at Y 3, 0, at Z negative 1, negative 1

If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'?

A. (1, −5)

B. (1, −3)

C. (1, 3)

D.(1, 5)

D.(1, 5)

Step-by-step explanation:

just took this test yesterday

D.(1, 5)

Step-by-step explanation:

d

step-by-step explanation:

i used the pitagoras theoreme

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct