In what quadrant would the image of point A (2,-1) be located if it is rotated 135° clockwise around point (1, -3)? Enter the numeric
value of the quadrant

The new point belongs to the fourth quadrant.

Step-by-step explanation:

The relative vector is:

The length of the vector is:

The angle with respect to the horizontal (+x direction) is:

The new angle with respect to the horizontal (+x direction) is:

The new point is:

The new point belongs to the fourth quadrant.

The new point A location is (1.69, -51267)

The quadrant is 4th quadrant

Step-by-step explanation:

Here we have a point rotating about another point, therefore we have;

Let point (1, -3) be = P

Therefore the length of line AP is given by the following relation;

With angle

Rotating through 135° clockwise gives;

63° - 135° = 72° Due south of east from P

The coordinates is then given as follows;

y coordinates = -3 - sin 72×√5 = -5.1267

The x coordinates will be 1 + cos 72×√5 = 1.69

The coordinate of the new point A location = (1.69, -51267)

Therefore the quadrant remains the 4th quadrant.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: