What is the missing constant term in the perfect square that starts with
x2+14xx^2+14x
x
2
+14x
x, squared, plus, 14, x
?

49

Step-by-step explanation:

The expression is given below:

x^2 + 14x

Let y be the constant that will make the expression a perfect square. Therefore, the expression can be written as:

x^2 + 14x + y

Applying the formula b^2 = 4ac, we can easily obtain the value of y as shown below:

x^2 + 14x + y

Coefficient of x^2 (a) = 1

Coefficient of x (b) = 14

Constant (c) = y

b^2 = 4ac

14^2 = 4 x 1 x c

196 = 4c

Divide both side by the coefficient of c i.e 4

c = 196/4

c = 49

Thus, 49 must be added to the expression to make it a perfect square.

the answer is c)8

step-by-step explanaction: