A square's diagonal (hypotenuse) is 28V2. What is the length of each side?

In a square, all four sides are the same length. Imagine a square that has been cut by a diagonal. We have two triangles, each with the same length hypotenuse (diagonal length) and two equal side lengths. To find the length of each side, we can use the Pythagorean theorem.

I used x in place of a and b, as both side lengths are equal.

x^2 + x^2 = (28 )^2

2x^2 = 1568

x^2 = 784

x = 28

The length of each side is 28 units.

Hope this helps!! :)

Once it is a square, the lengths are the same. Considering that

a square's diagonal is , thus, each length measures 28.

You may use the pythagorean theorem:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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