Find the approximate value of each trigonometric function.
Given that sin0 = 0.312 where - <0 Since 0 lies in Quadrant II, where cos0 <0, cos is approximately

-0.95

Step-by-step explanation:

cos(theta) = sqrt(1 - sin²(theta))

= sqrt(1 - 0.312²)

= sqrt(0.902656)

= +/- 0.9500821017

Since cos is negative in quadrant 2,

cos(theta) = -0.95

256π units²   (answer b)

step-by-step explanation:

the formula for the surface area of a sphere of radius r

is             a = 4πr²

and so, if r = 8 units, then the surface area is:

a = 4π(8 units)² = 256π units²   (answer b)

the first dot plot best represents the data

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