“angle A = 32, AC = 9, BC = x. Find x to two decimal places, don’t forget to round properly based on the third decimal place.” Pls answer & explain thanks

Given:

Given that ABC is a right triangle.

The measure of ∠A is 32°.

The length of AC is 9 units.

The length of BC is x units.

We need to determine the value of x.

Value of x:

The value of x can be determined using the trigonometric ratio.

Thus, we have;

where θ = A, the side opposite to A is BC and hypotenuse is AC.

Thus, we have;

Substituting BC = x and AC = 9, we get;

Multiplying both sides by 9, we have;

Thus, the value of x is 4.77 units.

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step-by-step explanation: