Find the Area of the figure below, composed of a rectangle and one semicircle,
with another semicircle removed. Round to the nearest tenths place.

Given:

The given figure consists of a rectangle, a semicircle and another semicircle removed from it.

The length of the rectangle = 15 unit

The width of the rectangle = 10 unit

The diameter of the semicircle = 10 unit

So, the radius of the semicircle = 5 unit

To find the formula of given fig.

Formula:

The area of the given fig is

where,

be the area of the rectangle

be the area of the semicircle

be the area of the semi circle that needs to remove

Area of the rectangle , where, l be the length and b be the width

The area of the semicircle =

The area of the semicircle =

where, r be the radius.

Now,

Putting, l=15 and b = 10 we get,

sq unit

sq unit

Putting, r = 5 and π = 3.14 we get,

sq unit

sq unit

Similarly, sq unit

Therefore,

The area of the given figure = (150+39.25-39.25) sq unit

= 150 sq unit

Hence,

The area of the given figure is 150 sq unit.

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72