An airplane flies from point A to point B Point A is 40 kilometers from a ground signal at point C point B is 56 kilometers from the same ground signal if AB=80 find the measure of ACB to the nearest degree

and i also need help on this question
https://gyazo. com/26e45b41a327e780e03eccd4f3d7f4d c

ACB = 112°

Step-by-step explanation:

First form a sketch where will have a triangle sketch showing the points ABC with AB= 80km and CB = 56 km

Apply the law of cosine as;

c²=a²+b²-2ab*cos(C)

To get angle C;

C=arccos((a²+b²-c²)/(2ab))

Substitute values given in the equation as

C=arccos((40²+56²-80²)/(2*40*56))

C=arccos(-1664/4480)

C=112°

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

if i put something wrong your not gonna like it so rather not say nothing.