A basketball player makes 80% of her free throws. The random numbers below represent 20 trials for

a simulation. Let the numbers 0 to 7 represent a made free throw and let 8 to 9 represent a missed

free throw. Use this simulation to estimate the probability that the player makes both free throws.

(8,2) (9,3) (4,0) (5,8) (2,7) (2,0) (5,4) (8,0) (0,4) (9.1)

(9,6) (6,5) (4,4) (1,7) (0,4) (8,5) (8,8) (1,7) (3,5) (0,3)

0.6

Step-by-step explanation:

Given the simulation data

(8,2) (9,3) (4,0) (5,8) (2,7) (2,0) (5,4) (8,0) (0,4) (9.1)

(9,6) (6,5) (4,4) (1,7) (0,4) (8,5) (8,8) (1,7) (3,5) (0,3)

These pairs are:

(4,0)  (2,7) (2,0) (5,4)  (0,4) (6,5) (4,4) (1,7) (0,4) (1,7) (3,5) (0,3)

There are a total of 12 cases where the player makes both throws.

Therefore:

P(Player makes both throws)=12/20=0.6

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%