A quadratic function has an equation of f(x) = a(x + 3)2 – 4 and goes through
the point (-2, 2). What is the a-value of the equation?

  6

Step-by-step explanation:

Put the given point into the equation and solve for a.

  f(-2) = a(-2 +3)² -4 = a -4 = 2

  a = 6 . . . . . add 4

The a-value in the equation is 6.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632