Suppose a bag contains 5 balls numbered 1 through 5. In how many way scan you select 5 balls from the bag if there is no replacement after selection?

5

Step-by-step explanation:

We are being asked in how many ways an enumerated ball can be removed without any type of replacement, therefore it would be a combination without repetition:

nCr = n! / r! * (n-r)!

n, total number of balls, 5

r, specific number of balls, 1

5C1 = 5! / (1! * 4!) = 5

Therefore there are 5 ways to do the above.

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%