Both 2 and 5 are common factors of a number. the number is between 101 and 118. what is the number? give a reason for your answer.

The number would be 110.

Step-by-step explanation:

Since, both 2 and 5 are common factors of a number.

Then the number must be divisible or multiple of LCM(2, 5) i.e. 10,

Now, the numbers is between 101 and 118.

102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118

Since, only 110 is multiple of 10,

Hence, the required number which has both 2 and 5 as its factor is 110.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w