Find 3 consecutive even integers such that the sum of the squares of the first and second is 2 more than the third

Given:

Let the 3 consecutive even integers be x, x + 2 and x + 4.

Given that the sum of the squares of the first and the second integers is 2 more than the third integer.

We need to determine the 3 consecutive integers.

Value of x:

From the given, the expression can be written as,

Simplifying, we get;

Factoring the middle term, we get;

Since, the fraction is neither a even nor odd integer.

Thus, the value of x is -2.

Consecutive integers:

Substituting the value of x in the consecutive integers x, x + 2 and x + 4, we get;

Thus, the 3 consecutive integers are -2, 0 and 2.

rx and sx

step-by-step explanation:

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: