What is the value of a $2500 investment after it has grown by 6.3% for 10 years?

The value of the investment would be $4,075

Step-by-step explanation: The initial investment, that is, the principal is given as $2500, and it was invested for a period of 10 years at the rate of 6.3%. Using the simple interest calculation formula, the investment would have a present value as follows;

Interest = P x R x T

Where P = amount invested (2500), R = rate of interest (6.3 or 0.063) and T = number of years (10)

Interest = 2500 x 0.063 x 10

Interest = 1575

The value of the investment at 6.3% after 10 years is now;

Initial investment + Interest

2500 + 1575 = 4075

Therefore the value of the investment is $4,075

answer:

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).