Ayana and Tabitha recorded the amount of time spent on homework on ten school days. Graphs of their data are shown. A box plot titled Ayana's Time spent on homework. The number line goes from 0 to 4. The whiskers range from 0.5 to 3.5, and the box ranges from 1 to 2. A line divides the box at 1.8. Ayana’s Time Spent on Homework A box plot titled Tabitha's Time spent on homework. The number line goes from 0 to 4. The whiskers range from 1 to 2.5, and the box ranges from 1.5 to 2.25. A line divides the box at 2. Tabitha’s Time Spent on Homework Which best explains who spends more time on homework? Ayana, because she has a higher maximum time spent Ayana, because she has more variability in her time spent Tabitha, because she has a higher median time spent Tabitha, because she has more variability in her time spent

C

Step-by-step explanation:

person said it on reply to first answer sorry if wrong

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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