Find how long it takes (in seconds) for a car to travel when the car is going a speed of 20mph on a 100 foot track.

3.4 seconds

Step-by-step explanation:

First, you have to change 20mph to feet per seconds. To do this, multiply mphs by 1.4667. When you multiply 20mph by 1.4667, you get 29.3333 fps.

Divide 100 by 29.333 to get 3.40909478 (3.4) seconds

3.41 sec

Step-by-step explanation:

We need to use the formula: , where r is the rate of the object, t is the time, and d is the distance.

Here, we know that the distance is 100 ft and that the rate is 20 mph. However, let's change the distance to miles because the rate is in miles.

There are 5280 ft in 1 mile, so:

5280/1 = 100/x  ⇒  x = 100/5280

Then, d = 100/5280 miles and r = 20. Plug these in to find t:

100/5280 = 20t

t = (100/5280) / 20 hours

Now, we need to convert hours to seconds. There are 3600 seconds in 1 hour, so multiply our current t by 3600:

t = [(100/5280) / 20] * 3600 ≈ 3.41 sec

Hope this helps!

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?