H(x)=x 2 −1h, left parenthesis, x, right parenthesis, equals, x, squared, minus, 1 Over which interval does h hh have a negative average rate of change? Choose 1 Choose 1 (Choice A) A − 3 ≤ x ≤ 5 −3≤x≤5minus, 3, is less than or equal to, x, is less than or equal to, 5 (Choice B) B 1 ≤ x ≤ 4 1≤x≤41, is less than or equal to, x, is less than or equal to, 4 (Choice C) C − 3 ≤ x ≤ 1 −3≤x≤1minus, 3, is less than or equal to, x, is less than or equal to, 1 (Choice D) D − 1 ≤ x ≤ 5 −1≤x≤5minus, 1, is less than or equal to, x, is less than or equal to, 5 Show Calculator

(C)−3 ≤ x ≤ 1

Step-by-step explanation:

The average rate of change of function h over the interval , is given by this expression:

Given the function on the interval:− 3 ≤ x ≤ 1

The average rate of change:

Therefore, the function has a negative average rate of change over the interval − 3 ≤ x ≤ 1.

CHECK:

(A)Average rate of change of h(x) over the interval − 3 ≤ x ≤ 5=2

(B)Average rate of change of h(x) over the interval 1 ≤ x ≤ 4=5

(D)Average rate of change of h(x) over the interval − 1 ≤ x ≤ 5=4

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.