Jason empties his piggy bank and counted out exactly $10 in nickels, dimes and quarters. There were twice as many dimes as Nickels. There were twice as many quarters as dimes. How many nickels did they have ?

8 nickels

Step-by-step explanation:

Total Amount of Money owned by Jason=$10

1 nickel =$0.05

1 dime=$0.10

1 quarter =$0.25

If there were twice as many dimes as Nickels, then:

Also, there were twice as many quarters as dimes.

Therefore:

0.1d+0.05n+0.25q=100

Substituting d=2n and q=2d into the above relations

0.1(2n)+0.05n+0.25(2d)=10

0.2n+0.05n+0.25(2(2n))=10

0.2n+0.05n+1n=10

1.25n=10

n=8

q=2d=2X16=32

d=2n=2X8=16

Jason had 8 nickels

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: