Please help ASAP
Questions 1 and 2 plz

Take the sequence in 1a

The 10th term is 31

The 20th is 61

If you wanted to find these by continuing the series, you'd have to add 3 to the last number in the series, then 3 more, then 3 more, until you reach the 20th term. By this point, you will have added 3 to the first term 19 times. That's where the formula comes from. So here,

a = 4, the first term

n = 20, the number of the term we need

d = 3, how much we're adding each time between one term and the next

Then, to get the 20th term,

4 + (20 - 1) • 3 = 4 + (19 • 3) = 4 + 57 = 61

Answers

The 10th and 20th terms of each sequences are

a. 31; 61

b. 48; 98

c. 47; 97

(in c, you're adding the same d as in the sequence above, but your first term is one unit less)

d. -25; -75

(same thing as before, but now, d is negative)

e. 11.5; 16.5

(with d=1/2 or 0.5)

f. 6+1/2; 8+1/2

Use these to check your answers after applying the formula, but know that I calculated on the fly and didn't check these.

answer: the common difference is -0.10

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