Find the solution to the system 4x - y = -12 and -x - y = 3

x = -3 , y = 0

Step-by-step explanation:

Solve the following system:

{4 x - y = -12 | (equation 1)

-x - y = 3 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{4 x - y = -12 | (equation 1)

0 x - (5 y)/4 = 0 | (equation 2)

Multiply equation 2 by 4/5:

{4 x - y = -12 | (equation 1)

0 x - y = 0 | (equation 2)

Multiply equation 2 by -1:

{4 x - y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Add equation 2 to equation 1:

{4 x+0 y = -12 | (equation 1)

0 x+y = 0 | (equation 2)

Divide equation 1 by 4:

{x+0 y = -3 | (equation 1)

0 x+y = 0 | (equation 2)

Collect results:

{x = -3 , y = 0

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation: