5x – 7y= 58
y = -x - 2

X=
Y=

x = 11/3 , y = -17/3

Step-by-step explanation:

Solve the following system:

{5 x - 7 y = 58 | (equation 1)

y = -x - 2 | (equation 2)

Express the system in standard form:

{5 x - 7 y = 58 | (equation 1)

x + y = -2 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x - 7 y = 58 | (equation 1)

0 x+(12 y)/5 = (-68)/5 | (equation 2)

Multiply equation 2 by 5/4:

{5 x - 7 y = 58 | (equation 1)

0 x+3 y = -17 | (equation 2)

Divide equation 2 by 3:

{5 x - 7 y = 58 | (equation 1)

0 x+y = (-17)/3 | (equation 2)

Add 7 × (equation 2) to equation 1:

{5 x+0 y = 55/3 | (equation 1)

0 x+y = -17/3 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 11/3 | (equation 1)

0 x+y = -17/3 | (equation 2)

Collect results:

{x = 11/3 , y = -17/3

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane