"A bicycle factory runs two assembly lines, A and B. 95% of line A's products pass inspection and 93% of line B's products pass inspection. 60% of the factory's bikes come off assembly line B and the rest come off line A. Find the probability that one of the factory's bikes did not pass inspection and came off assembly line Upper A."

0.02

Step-by-step explanation:

Since 60% of the factory's bikes come off assembly line B, Therefore:

The probability that the factory's bikes come off assembly line B = 60% = 0.6

Percentage line B's products pass inspection  = 93% = 0.93

Percentage line B's products that do not pass inspection = 1 - 0.93 = 0.07

The probability that the factory's bikes come off assembly line A = 1 - 0.6 = 0.4

Percentage line A's products pass inspection  = 95% = 0.95

Percentage line A's products that do not pass inspection = 1 - 0.95 = 0.05

Let D represent those that passes inspection and D' represent those that do not pass inspection.

P(A ∩  D') = P(A) × P(D'/A) = 0.4 × 0.05 = 0.02

P()bikes did not pass inspection and came off assembly line A) = P(A ∩  D') =  0.02

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

answer: do we write it

step-by-step explanation: