Consider the problem of distributing 10 distinct books among three different people with each person getting at least one book. Explain why the following solution strategy is wrong: first select a book to give to the first person in 10 ways; then select a book to give to the second person in nine ways; then select a book to give to the third person in eight ways; and finally distribute the remaining seven books in 73 ways.

The strategy used is not well, because it becomes very complex and very difficult to calculate the ways, it would play one by one, that is, despite making sense, the last part of the way to distribute the books how is it obtained? why would it be like this?

There is a much more effective way of solving the problem, and that is to divide it by cases.

Case 1:

Choose four books from the 10 available books and give them to the first student

Then choose three books from the remaining six books and give them to the second student.

Finally, give the remaining three books to the last student

Case 2:

Choose three books from the 10 available books and give them to the first student

Then choose four books from the remaining seven books and give them to the second student.

Finally, give the remaining three books to the last student

Case 3:

Choose three books from the 10 available books and give them to the first student

Then choose three books from the remaining seven books and give them to the second student.

Lastly, give the remaining four books to the last student

First it is to calculate the number number in each case by means of combinations, multiply the options per case and then add the final value in each case.

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1