Suppose a box contains 10 defective batteries and 14 good batteries. If 2 batteries are drawn from the box without replacement, what is the probability that the following will occur? (Enter your probabilities as fractions.) (a) the first one is good and the second one is defective (b) the first one is defective and the second one is good (c) one of the batteries drawn is good and one of them is defective

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

what is the answer?

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step-by-step explanation: