The square of a positive number increased by twice the number equals three. Find the number

1

Step-by-step explanation:

Let the number be x

x² + 2x = 3

x² + 2x - 3 = 0

Product  = -3

Sum =2

Factors = 3 * (-1)

x² + 3x - x - 3 = 0

x*(x+3) - (x + 3) = 0

(x + 3)(x - 1) = 0

Ignore x + 3 because the number is a positive number

x - 1 = 0

x = 1

The number is 1

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°