A roulette wheel in Las Vegas has 38 possible outcomes. Of those 38 outcomes, 18 are red, 18 are black, and 2 are green. Suppose you bet 2 dollars on the outcome being red. Now, assume that the casino will return your investment and give you an additional 2 dollars if you win, but will keep your 2 dollars if you lose. How much money should you expect to win each game

Expected value = - 0.1026

Step-by-step explanation:

Given that

Possible outcomes = 38

While the required outcome are red, 18 are black, and 2 are green

The probability of winning will be

18/ 38 = 0.474

Where winning will be

2 × 0.474 = 0.948

The probability of losing

20/38 = 0.5253

Where losing will be

- 2 × 0.5253 = -1.0506

Expected value = 0.948 + (- 1.0506)

Expected value = - 0.1026

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: