At a given time it is noted that the buoy moves a total of 5.5 feet from its low point to its high point, and that it returns to its high point every 8 seconds. Write an equation that describes the motion of the buoy if it is at its high point at time t

The equation is

Step-by-step explanation:

Considering the buoy as a solid ball performing the simple harmonic motion. At any time t, the angular velocity of the ball be  ω  and the maximum displacement for the ball is A also its amplitude.

So,

The equation for the displacement can be given as   y  =  A c o s (ω t) .

Lets find the amplitude as the question says that the buoy moves from its low point to its high point meaning that the amplitude is half of it as we consider it from origin.

⇒ Amplitude, ft

⇒ Angular velocity,     ...as time period (T)  = 10 sec

To find the equation we have to arrange them in .

Plugging the values in the above equation.

⇒

⇒  

Equation that describes the motion of the buoy if it is at its high point at time t is

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer