How would you explain the relationship between the real zero(s) of the function and x-intercept(s) of the graph? Since the graph crosses the x-axis at x = – 2, the function has a real zero of x = – 2. Since the graph never crosses the x-axis, the function has no real zeros. Since the graph eventually crosses the x-axis, the function has a real zero. Since the graph crosses the y-axis at 1/9, the function results in a real zero of x = 1/9?.

12/11c

or

12

c

11

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the workers who do no drive has no reasonable reason to buy gasoline due to they don't have anything to use it for

the answer is ! ?