The radius of the base of a cone is decreasing at a rate of 2 22 centimeters per minute. The height of the cone is fixed at 9 99 centimeters. At a certain instant, the radius is 13 1313 centimeters. What is the rate of change of the volume of the cone at that instant (in cubic centimeters per minute)?

The Volume is decreasing at a rate of per minute.

Step-by-step explanation:

Given a cone of radius r and perpendicular height h

Volume of the cone,

Since the height of the cone is fixed, the rate of change of the volume of the Cone, is given as:

We are to determine the rate of change of the Volume, V when:

The radius is decreasing at a rate of 2 cm per minute,  

Height, h=9 cm

Radius = 13cm

The Volume is decreasing at a rate of  per minute.

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: