In a certain Algebra 2 class of 28 students, 8 of them play basketball and 14 of them play baseball. There are 12 students who play neither sport. What is the probability that a student chosen randomly from the class plays basketball or baseball

Step-by-step explanation:

Total Number of students, the Universal Set =28

Let the number of those who play basketball =B

Let the number of those who play baseball =n

Number who play neither sport, =12

From Set Theory,

Since we want to determine the probability that a student chosen randomly from the class plays basketball or baseball, we only simply exclude those who play neither sports.

Mathematically,From Set Theory,

The Probability that a student chosen randomly from the class plays basketball or baseball

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it