Mathematics, 21.04.2020 16:10 AshantiLiz990
Un fabricante de componentes electronicos puede usar indistintamente dos tipos de plastico . La resistencia a la ruptura del este plástico es importante. Se sabe que y1 =
y2 = 1
psi. A partir de una muestra aleatoria de tamano n1 = 10 y n2 = 12 se obtiene que
x= 162.6 y x = 155. La compañÃa no adoptará el plástico 1 a menos que su resistencia 2
media a la ruptura exceda al plastico 2 en al menos 10 psi. Con base a esta informacion, ¿deberá usar el plástico 1?
Answers: 1
Mathematics, 21.06.2019 15:10
6x - 8 = 16 solve the following equation. then place the correct number in the box provided.
Answers: 2
Mathematics, 21.06.2019 19:00
Simplify. −4x^2 (5x^4−3x^2+x−2) −20x^6−12x^4+8x^3−8x^2 −20x^6+12x^4−4x^3+8x^2 −20x^8+12x^4−4x^2+8x −20x^6+12x^4+4x^3−8x^2
Answers: 1
Mathematics, 21.06.2019 20:30
Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.
Answers: 1
Mathematics, 21.06.2019 21:00
Oliver read for 450 minutes this month his goal was to read for 10% more minutes next month if all of her medicine go how many minutes will you read all during the next two months
Answers: 3
Un fabricante de componentes electronicos puede usar indistintamente dos tipos de plastico . La resi...
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