A large drain and a small drain are opened to drain a pool. The large drain can empty the pool in 2 h. After both drains have been open for 1 h, the large drain becomes clogged and is closed. The small drain remains open and requires 10 more hours to empty the pool. How long would it have taken the small drain, working alone, to empty the pool?

22

Step-by-step explanation:

Let X be the time for only a small drain, the work completed would be unity.

 The small drain has been open for a total of 11 hours, one hour next to the large one, and 10 hours alone.

We have that large drainage can accomplish this in 2 hours.

We have the following system:

1/2 + 11 / x = 1

solving, we have:

11 / x = 1 - 1/2

11 / x = 1/2

x = 11 * 2

x = 22

I mean it would take a total of 22 hours for the small drain alone

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

its totaly b

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