A contractor has $3,285 to spend for doors and hammers. Doors cost $75 each. He bought the greatest number of doors that he could buy. He will use the money he has remaining to buy hammers that cost $15 each. What is the greatest number of hammers the contractor can buy with the money he has remaining?

4 hammers

Step-by-step explanation:

step 1

Find out the greatest number of doors that the contractor could buy

Divide the total amount by the cost of each door

so

That means ----> The greatest number of doors that the contractor could buy are 43

step 2

Find the remaining money

The remaining money is equal to

step 3

Find the greatest number of hammers that the contractor can buy with the remaining money

Divide the remaining money by the cost of each hammer

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

answer is because 4×10=40

and 98×4= is 392

40,392