Which triangle could be drawn as it is described?

A. an obtuse triangle with sides measuring 5, 10, and 15

B. a scalene triangle with angles measuring 110° and 35°

C. an acute triangle with sides measuring 7, 4, and 2

D. an isosceles triangle with angles measuring 20° and 80°

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  D. isosceles triangle

Step-by-step explanation:

The side measures of choices A and C do not form a triangle of any sort.

The angle measures of choice B mean the remaining angle is ...

  180° -110° -35° = 35°

Two of the angles are the same measure, so the triangle will be isosceles, not scalene. No scalene triangle can be formed with those angle measures.

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The angle measures of choice D mean the remaining angle is ...

  180° -20° -80° = 80°

Two of the angles are the same measure, so an isosceles triangle can be formed as described in choice D.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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step-by-step explanation: