In ΔIJK, the measure of ∠K=90°, KJ = 63, IK = 16, and JI = 65. What ratio represents the sine of ∠I?

The sine of ∠I is represented by the ratio 63:65

Step-by-step explanation:

First, let's draw the triangle (see the picture below.)

Remember SOHCAHTOA? We need to use it here.

-sin = opposite/hypotenuse

-cos = adjacent/hypotenuse

-tan = opposite/adjacent.

Assuming that ∠I is Ф, we can see that its opposite side is equal to 63 and the hypotenuse is 65. Therefore,

2

step-by-step explanation:

vvvvv

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

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