What is the vertex and the equation for the axis of symmetry of 4x^2+3x+2

the vertex is at (-3/8, 23/16) and the axis of symmetry is x = 3/8

Step-by-step explanation:

The coefficients of the given quadratic are a = 4, b = 3 and c = 2.

The axis of symmetry is given by  

       -b                                        -3

x =   which here  is   x = = -3/8

       2a                                      2(4)

We use this result, x = -3/8, as the divisor in synthetic division to find the y-coordinate of the vertex.  Here's how:

-3/8          4           3            2

                          -3/2          -9/16

                 4          3/2          23/16

Thus, we know the vertex is at (-3/8, 23/16) and the axis of symmetry is x = 3/8.

8

step-by-step explanation: