The relationship between the distance run and the time for Amy can be represented by the equation Y equals 17.45X, where she ran Y meters in X seconds. which two equations could be used to represent the relationship for Brandon and Ruben

Question;

Assumption:

Let us assume Brandon's running speed is = 18.30 and

Ruben's running speed is = 16.50 and

The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;

Brandon → Y₁ = 18.3·X₁ and

Ruben → Y₂ = 16.5·X₂

Step-by-step explanation:

The equation is of the form

Y = 17.45·X

That is Amy ran Y meters in X seconds

Therefore we have

or the value 17.45 is the running speed of Amy

Therefore, where the running speed of Brandon is 18.30  and the running speed of Ruben is 16.50  we have

Y meters ran by Brandon in X seconds given by

Y₁ = 18.3·X₁ and

For Ruben we have Y meters ran in X seconds given by

Y₂ = 16.5·X₂.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752