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If cos A = 8/17, what is sin A?

cos2θ + sin2θ = 1, so sinθ = ±√(1 - cos2θ)

sinθ = ±√(225/289) = ± 15/17

= 15/17

Hope it helps!

We have sin² x + cos² x =1 for all real x.

Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².

However, remember that if x² = a², then x can be +a or –a.

Therefore, sin A = 15/17.

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