Cylindrical tank A has 9/10 of the radius and 9/10 of the height of cylindrical tank B. If tank A can hold 20 gallons, approximately how many gallons can tank B hold?

Tank B can hold 27.4 gallons

Step-by-step explanation:

Volume of a cylinder = πr^2h

Given that Cylindrical tank A has 9/10 of the radius and 9/10 of the height of cylindrical tank B

Let the radius of A = r

Radius of B = R

Height of A = h

Height of B = H

r = 0.9R and h = 0.9H

Volume of A = πr^2h

= π(0.9R)^2(0.9H)

= 2.29R^2H

Given that tank A can hold 20 gallons, approximately

20 = 2.29R^2H

R^2H = 20/2.29 = 8.73 (1)

Volume of B = πR^2H

Substitutes R^2H in equation (1) into Volume of B

Volume of B = 3.143 × 8.73

Volume of B = 27.4 gallons

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

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