The diameter of a circle has endpoints P(–6, –10) and Q(10, 6).

a. Find the center of the circle.
b. Find the radius. If your answer is not an integer, express it in radical form.
c. Write an equation for the circle.

The centre must be the midpoint of PQ

which would be C( (-10+4)/2 , (-2+6)/2 )

= C(-3,2)

radius is √( (4+3)^2 + (2-6)^2) = √65

equation:

(x+3)^2 + (y-2)^2 = 65

Step-by-step explanation:

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: